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In astrodynamics the specific orbital energy where
It is expressed in J/kg = m²s-2 or MJ/kg = km²s-2.
[edit] Equation forms for different orbitsFor an elliptical orbit specific orbital energy equation simplifies to[citation needed] where
For a parabolic orbit this equation simplifies to For a hyperbolic trajectory this specific orbital energy equation takes form In this case the specific orbital energy is also referred to as characteristic energy (or It is related to the hyperbolic excess velocity It is relevant for interplanetary missions. Thus, if orbital position vector ( [edit] Rate of changeFor an elliptical orbit the rate of change of the specific orbital energy with respect to a change in the semi-major axis is where
In the case of circular orbits, this rate is one half of the gravity at the orbit. This corresponds to the fact that for such orbits the total energy is one half of the potential energy, because the kinetic energy is minus one half of the potential energy. [edit] Additional energyIf the central body has radius R, then the additional energy of an elliptic orbit compared to being stationary at the surface is
[edit] ExamplesThe International Space Station has an orbital period of 91.74 minutes, hence the semi-major axis is 6738 km [1]. The energy is −29.6 MJ/kg [2]: the potential energy is −59.2 MJ/kg, and the kinetic energy 29.6 MJ/kg. Compare with the potential energy at the surface, which is −62.6 MJ/kg. The extra potential energy is 3.4 MJ/kg, the total extra energy is 33.0 MJ/kg. The average speed is 7.7 km/s, the net delta-v to reach this orbit is 8.1 km/s (the actual delta-v is typically 1.5–2 km/s more for atmospheric drag and gravity drag). The increase per meter would be 4.4 J/kg; this rate corresponds to one half of the local gravity of 8.8 m/s² [3]. For an altitude of 100 km (radius is 6471 km): The energy is −30.8 MJ/kg [4]: the potential energy is −61.6 MJ/kg, and the kinetic energy 30.8 MJ/kg. Compare with the potential energy at the surface, which is −62.6 MJ/kg. The extra potential energy is 1.0 MJ/kg, the total extra energy is 31.8 MJ/kg. The increase per meter would be 4.8 J/kg; this rate corresponds to one half of the local gravity of 9.5 m/s². The speed is 7.8 km/s [5], the net delta-v to reach this orbit is 8.0 km/s [6]. Taking into account the rotation of the Earth, the delta-v is up to 0.46 km/s less (starting at the equator and going east) or more (if going west). [edit] Applying thrustAssume:
Then the time-rate of change of the specific energy of the rocket is The change of the specific energy of the rocket per unit change of delta-v is which is |v| times the cosine of the angle between v and a. Thus, when applying delta-v to increase specific orbital energy, this is done most efficiently if a is applied in the direction of v, and when |v| is large. If the angle between v and g is obtuse, for example in a launch and in a transfer to a higher orbit, this means applying the delta-v as early as possible and at full capacity. See also gravity drag. When passing by a celestial body it means applying thrust when nearest to the body. When gradually making an elliptic orbit larger, it means applying thrust each time when near the periapsis. When applying delta-v to decrease specific orbital energy, this is done most efficiently if a is applied in the direction opposite to that of v, and again when |v| is large. If the angle between v and g is acute, for example in a landing (on a celestial body without atmosphere) and in a transfer to a circular orbit around a celestial body when arriving from outside, this means applying the delta-v as late as possible. When passing by a planet it means applying thrust when nearest to the planet. When gradually making an elliptic orbit smaller, it means applying thrust each time when near the periapsis. If a is in the direction of v: [edit] Earth orbits
[edit] See also
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