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In mathematics, a local field is a special type of field that is a locally compact topological field with respect to a non-discrete topology.[1] Given such a field, an absolute value can be defined on it. There are two basic types of local field: those in which the absolute value is Archimedean and those in which it is non-Archimedean. In the first case, one calls the local field an archimedean local field, in the second case, one calls it a non-archimedean local field. There is an equivalent definition of non-archimedean local field given below. Local fields arise naturally in number theory as completions of global fields. Every local field is isomorphic (as a topological field) to one of the following:
[edit] Non-Archimedean local field theoryFor a non-archimedean local field F (with absolute value denoted by |·|), the following objects are very important:
One often talks about the (discrete) valuation of a non-archimedean local field. This is a map
One generally chooses c such that v surjects onto An equivalent definition of a non-archimedean local field is that it is a field that is complete with respect to a discrete valuation and whose residue field is finite. [edit] Examples
[edit] Induced absolute valueGiven a locally compact topological field K, an absolute value can be defined as follows. First, consider the additive group of the field. As a locally compact topological group, it has a unique (up to positive scalar multiple) Haar measure μ. The absolute value is defined so as to measure the change in size of a set after multiplying it by an element of K. Specifically, define |·| : K → R by[2] for any measurable subset X of K (with 0 < μ(X) < ∞). This absolute value does not depend on X nor on the choice of Haar measure (since the same scalar multiple ambiguity will occur in both the numerator and the denominator). Given such an absolute value on K, a new induced topology can be defined on K. This topology is the same as the original topology.[3] Explicitly, for a positive real number m, define the subset Bm of K by Then, the Bm make up a neighbourhood basis of 0 in K. [edit] See also[edit] Notes[edit] References
[edit] Further reading
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